🧪 Periodic Table Quiz

This is the real program, converted to run on the web with every rule kept exactly the same — type your answer and press Enter, just like running it in Python.

👨‍💻 The original Python source code (with the comments they wrote themselves)

import random
periodic = {'Hydrogen':'H','Helium':'He','Lithium':'Li',
'Beryllium':'Be','Boron':'B','Carbon':'C','Nitrogen':'N',
'Oxygen':'O','Fluorine':'F','Neon':'Ne','Sodium':'Na',
'Magnesium':'Mg','Aluminium':'Al','Silicon':'Si','Phosphorus':'P',
'Sulfur':'S','Chlorine':'Cl','Argon':'Ar','Potassium':'K',
'Calcium':'Ca','Scandium':'Sc','Titanium':'Ti','Vanadium':'V',
'Chromium':'Cr','Manganese':'Mn','Iron':'Fe','Cobalt':'Co',
'Nickel':'Ni','Copper':'Cu','Zinc':'Zn','Gallium':'Ga',
'Germanium':'Ge','Arsenic':'As','Selenium':'Se','Bromine':'Br',
'Krypton':'Kr'}

print("\033[4mPeriodic Table Atomic number 1-36\033[0m")

def scoring():
    if answer == periodic[e]:
        print('\033[4mCORRECT\033[0m')
        print('--------------------')
        periodic.pop(e)
    else:
        print('\033[4mWRONG\033[0m')
        print(periodic[e])
        print('--------------------')

while periodic != {}:
    element = random.choice(list(periodic.items()))
    e = element[0]
    print(e)
    answer = input('Short word for this element is...\n==> ').capitalize()
    scoring()

print('Well done you answered all 36 element')